Luật toán tích phân xác định

	$\underset{a}{\overset{a}{\int }}f(x)dx=0$
	$\underset{a}{\overset{b}{\int }}f(x)dx=-\underset{b}{\overset{a}{\int }}f(x)dx$
	$\underset{a}{\overset{b}{\int }}f(x)dx=\underset{a}{\overset{c}{\int }}f(x)dx+\underset{c}{\overset{b}{\int }}f(x)dx$
	$\underset{a}{\overset{b}{\int }}[f(x)\pm g(x)]dx=\underset{a}{\overset{b}{\int }}f(x)dx\pm \underset{a}{\overset{b}{\int }}g(x)dx$
	$\underset{a}{\overset{b}{\int }}kf(x)dx=k\underset{a}{\overset{b}{\int }}f(x)dx$
	$\underset{a}{\overset{b}{\int }}ndx=nx=nb-na=n(b-a)$